Optimal. Leaf size=262 \[ -\frac{a^4}{160 d (a \sin (c+d x)+a)^5}+\frac{a^3}{256 d (a-a \sin (c+d x))^4}-\frac{9 a^3}{256 d (a \sin (c+d x)+a)^4}+\frac{5 a^2}{192 d (a-a \sin (c+d x))^3}-\frac{47 a^2}{384 d (a \sin (c+d x)+a)^3}+\frac{57 a}{512 d (a-a \sin (c+d x))^2}-\frac{187 a}{512 d (a \sin (c+d x)+a)^2}+\frac{61}{128 d (a-a \sin (c+d x))}-\frac{315}{256 d (a \sin (c+d x)+a)}-\frac{\csc (c+d x)}{a d}-\frac{437 \log (1-\sin (c+d x))}{512 a d}-\frac{\log (\sin (c+d x))}{a d}+\frac{949 \log (\sin (c+d x)+1)}{512 a d} \]
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Rubi [A] time = 0.290825, antiderivative size = 262, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {2836, 12, 88} \[ -\frac{a^4}{160 d (a \sin (c+d x)+a)^5}+\frac{a^3}{256 d (a-a \sin (c+d x))^4}-\frac{9 a^3}{256 d (a \sin (c+d x)+a)^4}+\frac{5 a^2}{192 d (a-a \sin (c+d x))^3}-\frac{47 a^2}{384 d (a \sin (c+d x)+a)^3}+\frac{57 a}{512 d (a-a \sin (c+d x))^2}-\frac{187 a}{512 d (a \sin (c+d x)+a)^2}+\frac{61}{128 d (a-a \sin (c+d x))}-\frac{315}{256 d (a \sin (c+d x)+a)}-\frac{\csc (c+d x)}{a d}-\frac{437 \log (1-\sin (c+d x))}{512 a d}-\frac{\log (\sin (c+d x))}{a d}+\frac{949 \log (\sin (c+d x)+1)}{512 a d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \frac{\csc ^2(c+d x) \sec ^9(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{a^9 \operatorname{Subst}\left (\int \frac{a^2}{(a-x)^5 x^2 (a+x)^6} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^{11} \operatorname{Subst}\left (\int \frac{1}{(a-x)^5 x^2 (a+x)^6} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^{11} \operatorname{Subst}\left (\int \left (\frac{1}{64 a^8 (a-x)^5}+\frac{5}{64 a^9 (a-x)^4}+\frac{57}{256 a^{10} (a-x)^3}+\frac{61}{128 a^{11} (a-x)^2}+\frac{437}{512 a^{12} (a-x)}+\frac{1}{a^{11} x^2}-\frac{1}{a^{12} x}+\frac{1}{32 a^7 (a+x)^6}+\frac{9}{64 a^8 (a+x)^5}+\frac{47}{128 a^9 (a+x)^4}+\frac{187}{256 a^{10} (a+x)^3}+\frac{315}{256 a^{11} (a+x)^2}+\frac{949}{512 a^{12} (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{\csc (c+d x)}{a d}-\frac{437 \log (1-\sin (c+d x))}{512 a d}-\frac{\log (\sin (c+d x))}{a d}+\frac{949 \log (1+\sin (c+d x))}{512 a d}+\frac{a^3}{256 d (a-a \sin (c+d x))^4}+\frac{5 a^2}{192 d (a-a \sin (c+d x))^3}+\frac{57 a}{512 d (a-a \sin (c+d x))^2}+\frac{61}{128 d (a-a \sin (c+d x))}-\frac{a^4}{160 d (a+a \sin (c+d x))^5}-\frac{9 a^3}{256 d (a+a \sin (c+d x))^4}-\frac{47 a^2}{384 d (a+a \sin (c+d x))^3}-\frac{187 a}{512 d (a+a \sin (c+d x))^2}-\frac{315}{256 d (a+a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 6.20331, size = 240, normalized size = 0.92 \[ \frac{a^{11} \left (\frac{61}{128 a^{11} (a-a \sin (c+d x))}-\frac{315}{256 a^{11} (a \sin (c+d x)+a)}+\frac{57}{512 a^{10} (a-a \sin (c+d x))^2}-\frac{187}{512 a^{10} (a \sin (c+d x)+a)^2}+\frac{5}{192 a^9 (a-a \sin (c+d x))^3}-\frac{47}{384 a^9 (a \sin (c+d x)+a)^3}+\frac{1}{256 a^8 (a-a \sin (c+d x))^4}-\frac{9}{256 a^8 (a \sin (c+d x)+a)^4}-\frac{1}{160 a^7 (a \sin (c+d x)+a)^5}-\frac{\csc (c+d x)}{a^{12}}-\frac{437 \log (1-\sin (c+d x))}{512 a^{12}}-\frac{\log (\sin (c+d x))}{a^{12}}+\frac{949 \log (\sin (c+d x)+1)}{512 a^{12}}\right )}{d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.104, size = 229, normalized size = 0.9 \begin{align*}{\frac{1}{256\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{4}}}-{\frac{5}{192\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}+{\frac{57}{512\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{61}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{437\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) }{512\,da}}-{\frac{1}{160\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{5}}}-{\frac{9}{256\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{47}{384\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{187}{512\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{315}{256\,da \left ( 1+\sin \left ( dx+c \right ) \right ) }}+{\frac{949\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{512\,da}}-{\frac{1}{da\sin \left ( dx+c \right ) }}-{\frac{\ln \left ( \sin \left ( dx+c \right ) \right ) }{da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.02458, size = 331, normalized size = 1.26 \begin{align*} -\frac{\frac{2 \,{\left (10395 \, \sin \left (d x + c\right )^{9} + 8475 \, \sin \left (d x + c\right )^{8} - 40035 \, \sin \left (d x + c\right )^{7} - 31395 \, \sin \left (d x + c\right )^{6} + 57309 \, \sin \left (d x + c\right )^{5} + 42269 \, \sin \left (d x + c\right )^{4} - 35941 \, \sin \left (d x + c\right )^{3} - 23621 \, \sin \left (d x + c\right )^{2} + 8224 \, \sin \left (d x + c\right ) + 3840\right )}}{a \sin \left (d x + c\right )^{10} + a \sin \left (d x + c\right )^{9} - 4 \, a \sin \left (d x + c\right )^{8} - 4 \, a \sin \left (d x + c\right )^{7} + 6 \, a \sin \left (d x + c\right )^{6} + 6 \, a \sin \left (d x + c\right )^{5} - 4 \, a \sin \left (d x + c\right )^{4} - 4 \, a \sin \left (d x + c\right )^{3} + a \sin \left (d x + c\right )^{2} + a \sin \left (d x + c\right )} - \frac{14235 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac{6555 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a} + \frac{7680 \, \log \left (\sin \left (d x + c\right )\right )}{a}}{7680 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.19109, size = 774, normalized size = 2.95 \begin{align*} \frac{16950 \, \cos \left (d x + c\right )^{8} - 5010 \, \cos \left (d x + c\right )^{6} - 2132 \, \cos \left (d x + c\right )^{4} - 1264 \, \cos \left (d x + c\right )^{2} - 7680 \,{\left (\cos \left (d x + c\right )^{10} - \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) - \cos \left (d x + c\right )^{8}\right )} \log \left (\frac{1}{2} \, \sin \left (d x + c\right )\right ) + 14235 \,{\left (\cos \left (d x + c\right )^{10} - \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) - \cos \left (d x + c\right )^{8}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 6555 \,{\left (\cos \left (d x + c\right )^{10} - \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) - \cos \left (d x + c\right )^{8}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (10395 \, \cos \left (d x + c\right )^{8} - 1545 \, \cos \left (d x + c\right )^{6} - 426 \, \cos \left (d x + c\right )^{4} - 152 \, \cos \left (d x + c\right )^{2} - 48\right )} \sin \left (d x + c\right ) - 864}{7680 \,{\left (a d \cos \left (d x + c\right )^{10} - a d \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) - a d \cos \left (d x + c\right )^{8}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.23339, size = 257, normalized size = 0.98 \begin{align*} \frac{\frac{56940 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac{26220 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} - \frac{30720 \, \log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{a} + \frac{30720 \,{\left (\sin \left (d x + c\right ) - 1\right )}}{a \sin \left (d x + c\right )} + \frac{5 \,{\left (10925 \, \sin \left (d x + c\right )^{4} - 46628 \, \sin \left (d x + c\right )^{3} + 75018 \, \sin \left (d x + c\right )^{2} - 54012 \, \sin \left (d x + c\right ) + 14721\right )}}{a{\left (\sin \left (d x + c\right ) - 1\right )}^{4}} - \frac{130013 \, \sin \left (d x + c\right )^{5} + 687865 \, \sin \left (d x + c\right )^{4} + 1462550 \, \sin \left (d x + c\right )^{3} + 1564350 \, \sin \left (d x + c\right )^{2} + 843525 \, \sin \left (d x + c\right ) + 184065}{a{\left (\sin \left (d x + c\right ) + 1\right )}^{5}}}{30720 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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